What is the distance between #(12 , (-3 pi)/4 )# and #(-1 , pi )#? Trigonometry The Polar System Polar Coordinates 1 Answer ali ergin Mar 6, 2016 #s~=11,31# Explanation: #x_1=12*cos(-3pi/4)" "x_1=8,485# #y_1=12 *sin (-3pi/4)" "y_1=-8,485# #x_2=-1*cos pi=1# #y_2=-1*sin pi=0# #s=sqrt((7,485)^2+(-8,485)^2)# #s=sqrt(56,025225+71,995225)# #s=sqrt (128,02045)# #s~=11,31# Answer link Related questions What are Polar Coordinates? How do you find the polar coordinates of the point? What is the difference between a rectangular coordinate system and a polar coordinate system? How do you graph polar coordinates? What careers use polar coordinates? How do you plot the point #A (5, -255^\circ)# and the point #B (3, 60^\circ)#? What does a polar coordinate system look like? How do you find the distance between 2 polar coordinates? For the given point #A(-4, frac{pi}{4})#, how do you list three different pairs of polar... How do you find the rectangular form of #(4, -pi/2)#? See all questions in Polar Coordinates Impact of this question 1909 views around the world You can reuse this answer Creative Commons License