# What is the distance between (3, 0)  and (6,6)?

Mar 5, 2018

$d = \sqrt{45} = 9 \cdot \sqrt{5} \approx 6.71$

#### Explanation:

${p}_{1} = \left(3 | 0\right)$
${p}_{2} = \left(6 | 6\right)$
${d}^{2} = {\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}$
$d = \sqrt{{\left(3 - 6\right)}^{2} + {\left(0 - 6\right)}^{2}}$
$d = \sqrt{9 + 36}$
$d = \sqrt{45} = 9 \cdot \sqrt{5} \approx 6.71$

Mar 5, 2018

I will show the method, you do the math!!

#### Explanation:

The distance between two points $\left({x}_{1} , {y}_{1}\right)$ and $\left({x}_{2} , {y}_{2}\right)$

is given by:

$\sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}$