Question

What is the domain and range of `d(s)= 0.009s^2`?

Answer 1

There is no restriction on the domain (no radicals or fractions)

Explanation:

So domain `=(-oo,+oo)`

Since `d(s)` is a square and therefore never negative, the range is restricted to non-negative numbers, the smallest being `d(0)=0`

So range `=(0,+oo)`