# What is the domain and range of d(s)= 0.009s^2?

Aug 24, 2015

So domain $= \left(- \infty , + \infty\right)$
Since $d \left(s\right)$ is a square and therefore never negative, the range is restricted to non-negative numbers, the smallest being $d \left(0\right) = 0$
So range $= \left(0 , + \infty\right)$