What is the domain and range of #f(x) = 1/(2x+4)#?

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Answer 1 · 2017-01-28T10:07:03

The domain is #x in RR- {-2}#
The range is #f(x) in RR-{0}#

As we cannot divide by #0#, #x!=-2#

The domain of #f(x)# is #D_f(x)=RR-{-2}#

#lim_(x->-oo)f(x)=lim_(x->-oo)1/(2x)=0^-#

#lim_(x->+oo)f(x)=lim_(x->+oo)1/(2x)=0^+#

Therefore,

#f(x)!=0#

The range of #f(x)# is #R_f(x)=RR-{0}#