What is the domain and range of #f(x)= 1/x#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

20
Jun 12, 2018

Answer:

Domain: #(-oo, 0) uu (0, + oo)#
Range: #(-oo, 0) uu (0, + oo)#

Explanation:

Your function is defined for any value of #x# except the value that will make the denominator equal to zero.

More specifically, your function #1/x# will be undefined for #x = 0#, which means that its domain will be #RR-{0}#, or #(-oo, 0) uu (0, + oo)#.

Another important thing to notice here is that the only way a fraction can be equal to zero is if the numerator is equal to zero.

Since the numerator is constant, your fraction has no way of ever being equal to zero, regardless of the value #x# takes. This means that the range of the function will be #RR - {0}#, or #(-oo, 0) uu (0, + oo)#.

graph{1/x [-7.02, 7.025, -3.51, 3.51]}

Was this helpful? Let the contributor know!
1500