# What is the domain and range of #f(x)=sqrt(4x+2)#?

##### 1 Answer

#### Explanation:

**The function is a Square Root Function**

To easily determine the domain and range, we should first convert the equation to **General Form:**

Where the point

**Let's now convert the given function to General Form:**

We can now simplify this by taking the square root of 4 outside:

**Therefore, from general form, we can now see that the endpoint of the graph is present at the point #(-1/2,0)# due to the fact that #b=-1/2# and #c=0#.**

Additionally from **General Form** we can see that neither

**For reference, the graph of the function #(y=sqrt(4x+2))# is below:**

graph{sqrt(4x+2) [-10, 10, -5, 5]}

**Therefore, the domain of the function can be expressed as:**

1. Domain:

2. Domain:

3. Domain: