What is the domain and range of #g(x)=2x^2-x+1#?
1 Answer
Feb 10, 2016
Domain:
Range:
Explanation:
So Domain
and we can determine its minimum value by re-writing its expression in vertex form:
#2x^2-x+1#
#=2(x^2-1/2xcolor(blue)(+(1/4)^2))+1 color(blue)(-1/8)#
#=2(x-1/4)^2+7/8#
#color(white)("XXXXXXXXX")# with vertex at#(1/4,7/8)#
So the Range
graph{2x^2-x+1 [-2.237, 3.24, -0.268, 2.47]}