What is the domain and range of #y=(3/2)x+1#?

1 Answer
Aug 22, 2015

Answer:

Domain: #RR# (all real numbers)
Range: #RR# (all real numbers)

Explanation:

This equation is in the form #y = mx+b#. That means it's just a straight line! In this case, the line has a slope of 3/2 and a y-intercept of 1, but that really doesn't matter. Because this line is diagonal, it is guaranteed that it will pass through every possible x-value AND every possible y-value. So, both the domain and range are "all real numbers", which can be shown like this: #RR#