# What is the domain and range of y=(3/2)x+1?

Domain: $\mathbb{R}$ (all real numbers)
Range: $\mathbb{R}$ (all real numbers)
This equation is in the form $y = m x + b$. That means it's just a straight line! In this case, the line has a slope of 3/2 and a y-intercept of 1, but that really doesn't matter. Because this line is diagonal, it is guaranteed that it will pass through every possible x-value AND every possible y-value. So, both the domain and range are "all real numbers", which can be shown like this: $\mathbb{R}$