# What is the domain and range of y =- sqrt(1 - x)?

Apr 20, 2018

$\therefore {D}_{f} : x \le 1$

${R}_{f} : y \le 0$

#### Explanation:

The term inside the Square root must be non-negative for the
function to be defined so ;

Domain of function is ${D}_{f}$ :

${D}_{f} : 1 - x \ge 0$

$\therefore {D}_{f} : x \le 1$

Since the function attains all the negative values and also $0$ .

$\therefore$the range of function is thus ${R}_{f} : y \le 0$

The graph of the function is given below :-