What is the domain and range of #y =sqrt(4x-1)#?

1 Answer
Feb 13, 2016

Answer:

Domain = #[1/4,oo)#.

Range = #[0,oo)#.

Explanation:

To find the x-intercept let #y=0# and solve for #x# to get #x=1/4#.

To find the y-intercept, let #x=0# to find that there is no real y-intercept.

Then draw the basic shape of the square root graph and deduce the domain (all possible allowed x-values as inputs) and the range (all possible allowed y-values as outputs).

graph{sqrt(4x-1) [-1.81, 10.68, -0.89, 5.353]}