What is the domain and range of # y= sqrt(x-1)#?

1 Answer
Feb 29, 2016

Answer:

Domain is #x>=1#. Range is all real numbers.

Explanation:

Note that #(x-1)# cannot take negative values of #y# is real. Assuming that we are working in real number domain, it is obvious x cannot take values less than one. Hence, domain is #x>=1#.

However, as #sqrt(x-1)#, #y# can take any value. Hencr, range is all real numbers.