# What is the domain and range of y =sqrt(x^2-1)?

Jun 29, 2016

the domain is
$x \in \mathbb{R} , b u t {x}^{2} - 1 \ge 0$
And the range is
$\left(0 , \infty\right)$

#### Explanation:

Real numbers exist in sqrt shouldn't be negative ,therefore I wrote this pattern ${x}^{2} - 1 \ge 0$
And the domain is $x \in \mathbb{R} , b u t {x}^{2} - 1 \ge 0$
And the range is $\left(0 , \infty\right)$