What is the domain and range of #y= sqrt (x^2 + 1)#?
Let's first search the domain. What we know about square root is that inside have to be a positive number.
We also know that
Let's find the range Now !
We know that x² is a positive or null value, so the minimum is for f(0).
So the minimum is 1. And because x² is divergent, there's no limits.
So the range is :