# What is the domain and range of #y= sqrt (x^2 + 1)#?

##### 1 Answer

Apr 4, 2018

Domain :

Range:

#### Explanation:

Let's first search the domain. What we know about square root is that inside have to be a positive number.

So :

We also know that

Let's find the range Now !

We know that x² is a positive or null value, so the minimum is for f(0).

So the minimum is 1. And because x² is divergent, there's no limits.

So the range is :