What is the domain and range of #y= (sqrt (x+4))/x#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Bio Nov 3, 2015 #x\in[-4,0)uu(0,oo)# #yin(-oo,oo)# Explanation: #x# cannot be less than -4 due to square root of a negative number. #x# cannot be zero due to division by zero. When #-4<=x<0#, #-oo<\y<=0#. When #0<\x<\oo#, #0<\y<\oo#. Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1250 views around the world You can reuse this answer Creative Commons License