# What is the domain and range of y=sqrt((x² - 8) )?

Domain: $\left(- \infty , - \sqrt{8}\right] \cup \left[\sqrt{8} , + \infty\right)$
Range: $y \ge 0$

#### Explanation:

For the domain of $y = \sqrt{{x}^{2} - 8}$
$x$ can not be in between $- \sqrt{8}$ and $\sqrt{8}$

Domain: $\left(- \infty , - \sqrt{8}\right] \cup \left[\sqrt{8} , + \infty\right)$

Range: $y \ge 0$

kindly see the graph
graph{(y-sqrt(x^2-8))=0[-20,20,-10,10]}

God bless....I hope the explanation is useful