What is the domain and range of #y=x^2#?

1 Answer
Aug 31, 2015

Answer:

Domain: #(-oo, + oo)#
Range: #[0, + oo)#

Explanation:

The function is defined for any value of #x in RR#, so its domain will have no restrictions. In interval notation, the function's domain will be #(-oo, + oo)#.

Since you're dealing with the square of a real number, the function can never be negative, regardless of the value of #x in RR#.

#x^2 >= 0", "(AA)x in RR#

This means that its range will be #[0, + oo)#.

graph{x^2 [-16.02, 16.02, -8.01, 8.01]}