What are the domain and the range of #y=sqrt(5-2x)# ? Thanks

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Answer 1 · 2018-06-21T11:43:13

The domain is #(-oo,5/2]#.
The range is #y in [0, +oo)#

What's under the square root sign is #>=0#

Therefore,

#5-2x>=0#

#=>#, #x<=5/2#

The domain is #(-oo,5/2]#

When #x=5/2#, #=>#, #y=0#

When #x->-oo#, #=>#, #y->+oo#

The range is #y in [0, +oo)#

graph{sqrt(5-2x) [-10, 10, -5, 5]}