Question

What is the Domain for: h(x)=ln(x+1)?

Answer 1

`(-1, +oo)`

Explanation:

`h(x) = ln(x+1)`

`lnx` is defined `forall x>0`

Hence, `ln(x+1)` is defined `forall (x+1) > 0 -> x> -1`

`:.` the domain of `h(x)` is `(-1, +oo)`

This can be seen from the graph of `h(x)` below:

graph{ln(x+1) [-11.25, 11.245, -5.62, 5.63]}