# What is the domain of f(x) = sqrt(x^2-144)?

May 18, 2018

$x \ge 12 \mathmr{and} x \le - 12$

#### Explanation:

${x}^{2} - 144 \ge 0$ or the value under the radical in imaginary:

${x}^{2} \ge 144$

$x \ge \pm \sqrt{144}$

$x \ge \pm 12$

$x \ge 12 \mathmr{and} x \le - 12$