# What is the domain of #f(x)=x/(x^3+8) #?

##### 1 Answer

#### Answer:

Domain:

#### Explanation:

You need to exclude from the function's domain any value of

This means that you need to exclude any value of

#x^3 + 8 = 0#

This is equivalent to

#x^3 + 2""^3 = 0#

You can factor this expression by using the formula

#color(blue)(a^3 + b^3 = (a+b) * (a^2 - ab + b^2))#

to get

#(x+2)(x^2 - 2x + 2^2) = 0#

#(x+2)(x^2 - 2x + 4) = 0#

This equation will have *three solutions*, but only one will be **real**.

#x+2 = 0 implies x_1 = -2#

and

#x^2 - 2x + 4 = 0#

#x_(2,3) = (-(2) +- sqrt((-2)^2 - 4 * 1 * 4))/(2 * 1)#

#color(red)(cancel(color(black)(x_(2,3) = (2 +- sqrt(-12))/2))) -># produces two complex roots

Since these two roots will be *complex numbers*, the only value of