What is the domain of #h(x) = (2x^2 + 5 )/ (sqrt(x-2))#?
In order to find the domain of
In other words, you cannot take the square root of a negative real number and get another real number as a solution.
Moreover, the expression under the square root cannot be equal to zero, since that would make the denominator equal to zero.
So, you need to have
#x - 2>0 implies x > 2#
In interval notation, the domain of the function is