Question

What is the domain of the function: `f(x) =sqrt(x^2 - 2x + 5)`?

Answer 1

`D_f=R`

Explanation:

`x^2-2x+5>=0`

`D=b^2-4ac=(-2)^2-4*1*5=4-20=-16`

Because `D<0` and `a=1>0`, expression `x^2-2x+5>0` for `AAx in R` and square root can be calculated. Hence,

`D_f=R`