# What is the electric current produced when a voltage of 15 V is applied to a circuit with a resistance of 6 Omega?

Mar 10, 2018

$2.5 a m p e r e s$

#### Explanation:

The formula needed to solve this question is defined by Ohms Law

$V = I R$

Which we can rearrange to find the current

$I = \frac{V}{R}$

Where

$I$ = Current ($a m p e r e s$)
$R$ = Resistance ($o h m s$)
$V$ = Potential Difference ($v o l$t$s$)

Substitute in the values you already have into the formula

$I$=$\frac{15}{6}$

$\therefore$ $I = 2.5 a m p e r e s$

Mar 11, 2018

$2.5 \setminus \text{A}$

#### Explanation:

We use Ohm's law here, which states that

$V = I R$

where $V$ is the voltage, $I$ is the current in amperes, and $R$ is the resistance in ohms.

We need to solve for current, so we can rearrange the equation into

$I = \frac{V}{R}$

Plugging in the given values, we get

$I = \frac{15 \setminus \text{V}}{6 \setminus \Omega}$

$= 2.5 \setminus \text{A}$

So, the electric current has a strength of $2.5$ amperes.