What is the equation for a circle with center (2, 5) and radius of 5?

1 Answer
Mar 13, 2017

#x^2+y^2-4x-10y+4=0#

Explanation:

The standard eqn for a circle

#"centre "(a,b)" radius "r:(x-a)^2+(y-b)^2=r^2#

In this case we have

#(x-2)^2+(y-5)^2=5^2#

now we multiply out and simplify

#x^2-4x+4+y^2-10y+25=25#

#x^2+y^2-4x-10y+4=0#