What is the equation of a circle whose center is #(0, -7)# and whose radius is #sqrt8#?

1 Answer
Mar 30, 2017

See the solution process below:

Explanation:

From: https://www.mathsisfun.com/algebra/circle-equations.html

The equation for a circle is:

#(x - color(red)(a))^2 + (y - color(red)(b))^2 = color(blue)(r)^2#

Where #(color(red)(a), color(red)(b))# is the center of the circle and #color(blue)(2)# is the radius of the circle.

Substituting the values from the problem gives:

#(x - color(red)(0))^2 + (y - color(red)(-7))^2 = color(blue)(sqrt(8))^2#

#x^2 + (y + color(red)(7))^2 = 8#