Question

What is the equation of a line, in general form, that passes through (-7,-2) and (1,6)?

Answer 1

`y=x+5`

Explanation:

line equation for given slope and a point is:

`y-y1 = m(x-x1)`

where m is the slope, x1 and y1 point coordinates.

m can be found by
`m= (y2-y1) / (x2-x1) => m=(6-(-2))/(1-(-7)) = 8/8=1`

now lets take a point (1,6) and m (1) then rewrite the equation:

`y-6 = 1 * (x-1) => y= x-1+6`
`y=x+5`