# What is the equation of the axis of symmetry for the graph of f(x) = -3x^2 - 6x + 4?

$f \left(x\right) = - 3 {x}^{2} - 6 x + 4 = - 3 \left({x}^{2} + 2 x\right) + 4 = - 3 \left({x}^{2} + 2 x + 1\right) + 3 + 4 = - 3 {\left(x + 1\right)}^{2} + 7 ,$
so the axis of symmetry is $x = - 1$ and the vertex $\left(- 1 , 7\right)$.