What is the equation of the axis of symmetry of #y=(x-3^2)+8#?

1 Answer
Shwetank Mauria
Sep 23, 2017

Axis of symmetry is #x-3=0# or #x=3#

Explanation:

As the equation is already in the vertex form i.e. #y=a(x-h)^2+k#,

in which case axis of symmetry is #x-h=0# and vertex is #(h,k)#.

Hence for #y=(x-3)^2+8#, axis of symmetry is #x-3=0# or #x=3#

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