# What is the equation of the circle with a center at #(3 ,1 )# and a radius of #1 #?

##### 1 Answer

Jan 20, 2016

#### Explanation:

The general form for the equation of a circle with a center at

#(x-h)^2+(y-r)^2=r^2#

We know that

#(h,k)rarr(3,1)=>h=3,k=1#

#r=1#

So the equation of the circle is

#(x-3)^2+(y-1)^2=1^2#

or, slightly more simplified (squaring the

#(x-3)^2+(y-1)^2=1#

The circle graphed:

graph{((x-3)^2+(y-1)^2-1)((x-3)^2+(y-1)^2-.003)=0 [-2.007, 9.093, -1.096, 4.454]}