Question

What is the equation of the line between `(10,3)` and `(-4,12)`?

Answer 1

`9x+14y-132=0`

Explanation:

The equation of a line is given by `y-y_1=m(x-x_1)` where `m=(y_2-y_1)/(x_2-x_1)`.

The gradient: `m=(12-3)/(-4-10)=9/-14`

The equation of the line is: `y-3=-9/14(x-10)`

`14y-42=-9x+90` multiply both sides by `14` and expand brackets

`9x+14y-132=0`