Question

What is the equation of the line between `(-11,4)` and `(7,-7)`?

Answer 1

The equation of the line in standard form is `11x +18y = -49`

Explanation:

The slope of the line passing through `(-11,4) and (7,-7)` is `m= (y_2-y_1)/(x_2-x_1)= (-7-4)/(7+11)= -11/18`

Let the equation of the line in slope-intercept form be `y=mx+c or y=-11/18x+c` The point (-11,4) will satisfy the equation . So, `4= -11/18*(-11)+c or c= 4-121/18= -49/18`

Hence the equation of the line in slope-intercept form is `y= -11/18x-49/18.`

The equation of the line in standard form is `y= -11/18x-49/18. or 18y =-11x-49 or 11x +18y = -49` {Ans]