Question

What is the equation of the line between `(-17,12)` and `(31,16)`?

Answer 1

`y=1/12x +161/12`

Explanation:

Gradient = `(16-12)/(31-(-17))` = `4/48 = 1/12`
Use `y-y1=m(x-x1)`
`y-16=1/12(x-31)`
`y=1/12x-31/12+16`
`y=1/12x +161/12`