What is the equation of the line between #(-3,-3)# and #(-4,1)#?

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Answer 1 · 2016-05-20T13:51:18

Equation of the line is #4x+y+15=0#

Equation of a line joining two points #(x_1,y_1)# and #(x_2,y_2)# is given by

#(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1)#

Hence equation of line joining #(-3,-3)# and #(-4,1)# is

#(x-(-3))/((-4)-(-3))=(y-(-3))/(1-(-3))#

or #(x+3)/((-4+3))=(y+3)/(1+3)#

or #(x+3)/(-1)=(y+3)/4#

or #4(x+3)=-y-3#

or #4x+y+12+3=0# or #4x+y+15=0#