# What is the equation of the line normal to #f(x)=3x^2 +x-5 # at #x=1#?

##### 1 Answer

Mar 28, 2016

#### Explanation:

We need to obtain first the slope m which is negative reciprocal of the slope of the tangent line at x=1 on the curve

Compute the first derivative

at

Compute

Determine the ordinate for the given abscissa

The point is at

Determine the Normal Line now using Point-Slope Form

See the graph of

graph{(y-3x^2-x+5)(x+7y+6)=0[-22,22,-10,10]}