What is the equation of the line passing through (5,4) and (-9,-2)?

1 Answer
Jun 9, 2016

The equation of the straight line is : 7y - 3x + 11 =0

Explanation:

Let A(x1,y1) = A(5,4)
and B(x2,y2) = B(-9,-2)

First find the slope of the line, using the formula :

m = (y2-y1)/(x2-x1)

m = (-6)/-14 = 3/7

Now using the point-slope form of a straight line :
y-y1=m(x-x1)

y-4=3/7*(x-5)

On simplifying, we get,
7y - 3x + 11 =0

graph{3/7*(x-5) +4 [-10, 10, -5, 5]}