What is the equation of the line passing through #(97,26)# and #(10,34)#?

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Answer 1 · 2016-12-21T22:42:18

#8x+87y-3038=0#

To find the gradient, do rise/run.

= #(34-26)/(10-97)#

= #8/-87=-8/87#

The equation is now #y=-8/87x + c#

The sub one of the coordinates to find c.

#34=-8/87(10) +c#

or #34= -80/87+c#

or #c=-34+80/87#

or #c=(34xx87+80)/87=3038/87#

The full equation is:

#y=-8/87x + 3038/87#

or #8x+87y-3038=0#