# What is the equation of the line with slope  m= 11/3  that passes through  (-17/15,-15/24) ?

Jan 8, 2016

3960x-1080y+3813=0#

#### Explanation:

If $A \left({x}_{1} , {y}_{1}\right)$ is a point on the line and $m$ is the slope of the line then the equation of line is given by
$y - {y}_{1} = m \left(x - {x}_{1}\right)$

Here $m = \frac{11}{3}$ and $A = \left(- \frac{17}{15} , - \frac{15}{24}\right)$

The required line is
$\implies y - \left(- \frac{15}{24}\right) = \frac{11}{3} \left(x - \left(- \frac{17}{15}\right)\right)$

$\implies y + \frac{15}{24} = \frac{11}{3} \left(x + \frac{17}{15}\right)$

$\implies y + \frac{15}{24} = \frac{11 x}{3} + \frac{187}{45}$

$\implies 1080 y + 675 = 3960 x + 4488$
$\implies 3960 x - 1080 y + 3813 = 0$