# What is the equation of the line with slope  m= -11/5  that passes through  (-13/15,-13/24) ?

May 16, 2017

See below.

#### Explanation:

Based on the given information, you can use the point-slope form equation to get the desired equations. In this case, you would plug in $m = - \left(\frac{11}{5}\right)$ for $m$ in the point-slope form, along with the x- and y-coordinates of $\left(- \frac{13}{15} , - \frac{13}{24}\right)$ for $x 1$ and $y 1$ in the equation. Then, you would get this:

$y - \left(- \frac{13}{24}\right) = \left(- \frac{11}{5}\right) \left(x - \left(- \frac{13}{15}\right)\right)$.

This can be simplified to:

$y + \frac{13}{24} = - \frac{11}{5} \left(x + \frac{13}{15}\right)$.

This would be your final answer, unless your instructor wants you to express the final answer in slope-intercept form, which is $y = m x + b$. I am not going to take the extra step since you have not specified what form the equation should be expressed in, but this would be your answer for the problem.

I hope that helps!