What is the equation of the line with slope # m= 5/7 # that passes through # (3/5,9/7) #?

1 Answer
May 8, 2017

See a solution process below:

Explanation:

We can use the point-slope formula to write an equation for the line in the problem. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

#(y - color(red)(9/7)) = color(blue)(5/7)(x - color(red)(3/5))#

If required, we can solve for #y# to put this equation in the slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y - color(red)(9/7) = (color(blue)(5/7) * x) - (color(blue)(5/7) * color(red)(3/5))#

#y - color(red)(9/7) = 5/7x - (color(blue)(color(black)(cancel(color(blue)(5)))/7) * color(red)(3/color(black)(cancel(color(red)(5)))))#

#y - color(red)(9/7) = 5/7x - 3/7#

#y - color(red)(9/7) + 9/7 = 5/7x - 3/7 + 9/7#

#y - 0 = 5/7x + 6/7#

#y = color(red)(5/7)x + color(blue)(6/7)#