What is the equation of the normal line of #f(x)=1/(1-2e^(x)# at #x=-1#?
First, we need to locate the point on x-y coordinate.
Meaning, we need
Now, we can take the derivative of
We have to find slope of the normal line so the ⟂ slope would be
Finally, we can plugin all the numbers in a point-slope equation. That will give us following: