What is the equation of the parabola that has a vertex at # (6, 0) # and passes through point # (3,18) #?

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Answer 1 · 2016-04-05T10:19:55

Equation of the parabola is
#(x-6)^2=1/2y#

It is a parabola which opens upward

#(x-h)^2=+4p(y-k)#

We have the given points Vertex #(h. k)=(6, 0)# and passing thru #(3, 18)#

solve for p using the given points

#(3-6)^2=+4p(18-0)#

#p=1/8#

We can now write the equation

#(x-h)^2=+4p(y-k)#

#(x-6)^2=1/2y#

God bless....I hope the explanation is useful.