# What is the equation of the parabola with axis intercepts of x=3, x=-4, and y=-2?

$y = \frac{1}{6} \left(x - 3\right) \left(x + 4\right)$
$y = f \left(x\right) = a \left(x - 3\right) \left(x + 4\right)$
$- 2 = f \left(0\right) = a \left(- 3\right) \cdot 4 R i g h t a r r o w a = \frac{2}{12}$