Question

What is the equivalent resistance of a circuit that contains three 10.0 resistors connected in parallel with a 6.0 V battery?

Answer 1

The equivalent resistanceis `=3.33Omega`

Explanation:

The equivalent resistance of `3` resistors in parallel is

`1/R_e=1/R+1/R+1/R=3/R`

Therefore,

`R_e=R/3`

As `R=10 Omega`

`R_e=10/3=3.33 Omega`