# What is the final concentration of 50.0 mL of a 2.00M solution, diluted to 500.0 mL?

$\text{Concentration"="Moles of stuff"/"Volume of solution}$ $=$ $0.20 \cdot m o l \cdot {L}^{-} 1$
$\frac{50.0 \times {10}^{- 3} \cancel{L} \times 2.00 \cdot m o l \cdot \cancel{{L}^{-} 1}}{500.0 \times {10}^{-} 3 \cdot L}$ $=$ ??mol*L^-1
Note that the answer is reasonable. If you read the question you have diluted the starting solution from $50.0 \cdot m L$ to $500.0 \cdot m L$, a tenfold dilution, so the final solution shoould be $10 \times$ as dilute.