What is the force between two small charged spheres having charges of 2 times 10^-72×10−7 C and 3 times 10^-73×10−7 C placed 30 cm apart in air?
1 Answer
Explanation:
We're asked to find the magnitude of the electric force between two point charges.
To do this, we can use the equation
F_"e" = k(|q_1q_2|)/(r^2)Fe=k|q1q2|r2
where
-
F_"e"Fe is the magnitude of the electric force (in newtons) -
kk is Coulomb's constant, equal to8.988xx10^9("N"·"m"^2)/("C"^2)8.988×109N⋅m2C2 -
q_1q1 andq_2q2 are the point charges (in coulombs), in no particular order -
rr is the distance between the charges (in meters)
We have:
-
k = 8.988xx10^9("N"·"m"^2)/("C"^2)k=8.988×109N⋅m2C2 -
q_1 = 2xx10^-7q1=2×10−7 "C"C -
q_2 = 3xx10^-7q2=3×10−7 "C"C -
r = 30r=30 "cm"cm = ul(0.30color(white)(l)"m"
Plugging in known values:
F_"e" = (8.988xx10^9("N"·cancel("m"^2))/(cancel("C"^2)))(|(2xx10^-7cancel("C"))(3xx10^-7cancel("C"))|)/((0.30cancel("m"))^2)