# What is the formula weight of Mg(BrO_4)_2?

Jan 8, 2017

$312.11 \frac{g}{\text{mol}}$

#### Explanation:

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

• Mg has a molar mass of 24.31 g/mol
• Br has an atomic weight of 79.90 g/mol
• O has an atomic weight of 16.00 g/mol

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{m a \ge n t a}{\text{24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol}}$