What is the free-fall acceleration at the surface of (a) the moon and (b) Jupiter?

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Apr 11, 2017

Answer:

#g_("moon")=1.62" " m/s^2#
#g_("Jupiter")=24.79" "m/s^2#

Explanation:

#"let us assume that there is an object with a mass of 'm' on the"# #"moon. The moon will attract this object."#

#cancel(m)*g_("moon")=G*(cancel(m)*M_("moon"))/r_("moon")^2#

#g_("moon")=G*M_("moon")/r_("moon")^2#

#"where "M_("moon")" mass of moon ,"r_("moon") " radius of moon"#

#g_("moon")=6.67*10^(-11)*(7.35*10^(22))/(1738000)^2#

#g_("moon")=1.62" " m/s^2#

#"for Jupiter: "#

#g_("Jupiter")=G*M_("Jupiter")/r_("Jupiter")^2#

#g_("Jupiter")=6.67*10^(-11)*(1.9*10^(27))/(71492000)^2#

#g_("Jupiter")=24.79" "m/s^2#

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