Question

What is the frequency of `f(theta)= sin 12 t - cos 5 t`?

Answer 1

Period: `2pi`
Frequency: `1/(2pi)`

Explanation:

Period of sin (12t) --> `(2pi)/12 = pi/6`
Period of cos (5t) --> `(2pi)/5`
Period of f(t) --> least common multiple of `pi/6 and (2pi)/5`

`pi/6` .........x(6)(2) ..... --> `2pi`

(2pi)/5 .........x (5) ......... --> `2pi`

Period of f(t) is `P = 2pi`
Frequency`= 1/P = 1/(2pi)`