Question

What is the frequency of `f(theta)= sin 2 t - cos 3 t`?

Answer 1

`2pi`

Explanation:

Period of sin (2t) ---> `(2pi)/2 = pi`
Period of cos (3t) ---> `(2t)/3`
Period of f(t) --> least multiple of `pi and (2pi)/3` --> `2pi`
`pi` x (2) ---> `2pi`
`(2pi)/3` x (3) ---> `2pi`