What is the frequency of #f(theta)= sin 6 t - cos 39 t #?

1 Answer
Nghi N
Jun 21, 2017

#F = 1/(2pi)#

Explanation:

Period of sin 6t --> #(2pi)/6 = pi/3#
Period of cos 39t --> #(2pi)/39#
Find common least multiple of #pi/3# and #(2pi)/39#
#pi/3# ... x ...(3)(2).... --> #2pi#
#(2pi)/39# ...x ... (39)... --> #2pi#
Period of f(t) --> #T = 2pi#
Frequency of f(t) --> # F = 1/T= 1/(2pi)#

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